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The Geometry of a DDR arrow
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dernalia
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0. PostPosted: Thu Oct 27, 2005 3:25 pm    Post subject: The Geometry of a DDR arrow Reply with quote

I made this at play practice yesturday
btw.. i missed the bottom segment length.. it should be:
(2(1/3)(1/4)(SquareRoot(2X^2)))


*All Expressions Anti Simplified for sake of those who don't as easily understand lowest terms


Last edited by dernalia on Thu Oct 27, 2005 3:52 pm, edited 2 times in total
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agent709 (orange)
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1. PostPosted: Thu Oct 27, 2005 3:29 pm    Post subject: Reply with quote

Thanks, now I can, ah... apply... this information to... stuff.

Honestly though, I actually do like it. Someone who likes DDR enough to anatomize the arrow.

You could make a nice graffiti stencil with this...
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quax94
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2. PostPosted: Thu Oct 27, 2005 3:30 pm    Post subject: Reply with quote

Are u a geomatry freak?
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dernalia
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3. PostPosted: Thu Oct 27, 2005 3:34 pm    Post subject: Reply with quote

heh... i'm a math freak in general... i like... EVERYTHING... algebra, geometry, trig... i have yet to take calculous... but.. yeah.. its fun.. although... the dyslexia that comes with being good at math is.. interesting...i do actually like everything though.. not just math..=p

I really like making things easy... for the sake of laziness... i typed all the elements into my calculator, assigning the atomic masses to variables representing the symbols... cause right now, in chem, we are doing stuff with mass and molar wait and stuff..
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mavrik_055
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4. PostPosted: Thu Oct 27, 2005 3:59 pm    Post subject: Reply with quote

dernalia wrote:
i have yet to take calculous

Yea...calculus...it sucks...
Now build a peicewise function of it so it can be graphed.BTW, Good jorb, i like. I should have my calc teacher check it for errors, tho...
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dernalia
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5. PostPosted: Thu Oct 27, 2005 4:24 pm    Post subject: Reply with quote

heh.. i would need a function for every line segment..=/

and all the angles are either 45, 90, or 135... and all right triangles... there shouldn't be any errors =/ .... And trisectors... hehehe... those are fun..
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Barbaloot
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6. PostPosted: Thu Oct 27, 2005 4:56 pm    Post subject: Reply with quote

sqrt(2)x is a much better way of saying sqrt(2x^2)

also, arent the arrows rounded at the corners?
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dernalia
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7. PostPosted: Thu Oct 27, 2005 4:59 pm    Post subject: Reply with quote

no... cause you need to take 2 times x^2 first...=p

the default ones are rounded....

but i didnt' feel like using trig at play practice =p
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Barbaloot
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8. PostPosted: Thu Oct 27, 2005 5:02 pm    Post subject: Reply with quote

dernalia wrote:
no... cause you need to take 2 times x^2 first...=p


Because of order of operations, 2x^2 means the same thing as 2(x^2). Thus, sqrt(2x^2) = sqrt(2)*sqrt(x^2) = sqrt(2)x
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dernalia
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9. PostPosted: Thu Oct 27, 2005 5:05 pm    Post subject: Reply with quote

true... heh... oops... oh well... i didn't feel like simplifying anything in the pic, cause.. that would require thought...=p
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ColorOfSakura
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10. PostPosted: Thu Oct 27, 2005 5:10 pm    Post subject: Reply with quote

ddrmaster5 wrote:
Are u a geomatry freak?


No, they just did that for their health.
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Boochypa
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11. PostPosted: Thu Oct 27, 2005 5:17 pm    Post subject: Reply with quote

mavrik_055 wrote:
Yea...calculus...it sucks...


No...no, it doesn't.
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dernalia
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12. PostPosted: Thu Oct 27, 2005 5:25 pm    Post subject: Reply with quote

I need to take up through calc 3-4 in college happy.gif yay engineering! happy.gif
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Synaesthesia
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13. PostPosted: Thu Oct 27, 2005 7:59 pm    Post subject: Re: The Geometry of a DDR arrow Reply with quote

dernalia wrote:
I made this at play practice yesturday
btw.. i missed the bottom segment length.. it should be:
(2(1/3)(1/4)(SquareRoot(2X^2)))


*All Expressions Anti Simplified for sake of those who don't as easily understand lowest terms


Because you can't figure that out without high school freshman geometry (or even earlier than that).

Hay /Chit-Chat, I was bored so I made this in my spare time, am I cool now?



Wherein the exponent is the optical depth along the tangent line of sight Z-sub-t, delta-gamma is the spectral width of channel N with band pass function psi (gamma), delta-omega is the angular field view of the instrument with response W(omega). The value of the exponent varies with the tangent height; effectively 0 at 100 km and generally increases downward. It's a combination of Rayleigh, aerosol, and gaseous species extinction.
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Phrekwenci
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14. PostPosted: Thu Oct 27, 2005 10:55 pm    Post subject: Reply with quote

What? (no, seriously)
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dernalia
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15. PostPosted: Fri Oct 28, 2005 3:32 am    Post subject: Reply with quote

uhm... i;ve yet to take a math class that advanced... =/.. i'm only in trig... care to explain that? formula thing?
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Synaesthesia
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16. PostPosted: Fri Oct 28, 2005 5:30 am    Post subject: Reply with quote

That function describes the irradiance (R-sub-N) of a given parcel of the atmosphere for any wavelength channel "N" at a specific height (Z-sub-T) as measured by the SAGE III data instrument's spectograph.
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Solar-Wind
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17. PostPosted: Fri Oct 28, 2005 10:45 am    Post subject: Reply with quote

dernalia wrote:
I need to take up through calc 3-4 in college happy.gif yay engineering! happy.gif


ditto.... yay quantum physics! happy.gif

calculus is sexy.
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dy▶◀monyte
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18. PostPosted: Fri Oct 28, 2005 1:35 pm    Post subject: Reply with quote

Solar-Wind wrote:
calculus is sexy.


Solar-Wind, your my hero
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zero_delocke
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19. PostPosted: Fri Oct 28, 2005 6:08 pm    Post subject: Reply with quote

Can it be? I have actually stumbled onto an intellegent thread in Chit-Chat? *gasp*

And Calculus is freakin' cool. I love all the theorems. Calculus isn't just about the numbers, mmaaannnnn. Its groovy.
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